Question

como resolvooo
4x-12+x(x-2)=3(x-2).(x-3)

Answer 1

4X- 12 + X² - 2X = (3X - 2X)* (X - 3)
4X- 12 + X² - 2X = 3X² - 9X -2X² + 6X
X² - 3X² + 2X² -4X - 2X + 9X - 6X - 12 = 0
- 3X = 12
X = - 4

Answer 2

Primeiro temos que usar a distributiva:
$4x-12+x(x-2)=3(x-2).(x-3)$ => $4x-12+x^2-2x=3x^2-9x-6x+18$ => $-12+x^2+2x=3x^2-15x+18$ => $-2x^2+17x-30=0$ => delta=$b^2-4ac$ => DELTA = $17^2-4.(-2).(-30)$ => DELTA = $289-240$ => DELTA = $49$ /
$x = \frac{-b \frac{+}{-} \sqrt{DELTA}}{2a}$ => $x = \frac{-17 \frac{+}{-} \sqrt{49}}{2(-2)}$ => $x1 = \frac{-17 + 7}{-4}$ => $x1 = \frac{-10}{-4}$ => $x1 = \frac{5}{2}$ /
$x2 = \frac{-17 - 7}{-4}$ => $x2 = \frac{-24}{-4}$ => $x2 = 6$