Question

como resolvo :
(x-4)²+5x (x-1) = 16 ?

Answer 1

Olá :

*$(x-4)^{2} +5x (x-1) =16$

*$x^{2} -8x+16+5 x^{2} -5=16$

*$6 x^{2} -8x-5=0$

*-8.-8-4.6.-5=184

*8+-√184/6

*x'= 8+√184/6 = 4+√184/3

*x"= 8-√184/6= 4-√184/3