Question

Como resolvo o sistema abaixo
{X+Y=10
{X.Y=16

Answer 1

{x+y=10
{x.y=16

x=10-y

(10-y).y=16
10y-y²=16
-y²+10y-16=0

∆=b²-4ac
∆=(10)²-4.(-1).(-16)
∆=100+4.(-16)
∆=100-64
∆=36

x=-b±√∆
2a
x=-(10)±√36
2.(-1)
x=-10±6
-2

x'=-10+6
-2
x'=-4
-2
x'=2

x"=-10-6
-2
x"=-16
-2
x"=8