Question

Como resolvo log 8=3 com base x

Answer 1

og(a) b=log b/log a ==>mudança de base 

log a/b=log a-log b 
log a*b=log a+log b 

b*log a= log a^b 

(1/b)*log a= log a^(1/b) 

log 10 =1, pois 10^1=10 

log 5= log10/2=log 10 - log 2=1-log 2 

Answer 2

LOG 8 = 3
        x

x³ = 8 ==> x³ = 2³ ==> x = 2