Question

Como resolvo log 27 na base 3√3?

Answer 1

$(3\sqrt{3})^x = 27 \\ \\ (\sqrt{27})^x = 27 \\ \\ (\sqrt{3^3})^x = 3^3 \\ \\ (3^{\frac{3}{2}})^x = 3^3 \\ \\ \not3^{\frac{3x}{2}} = \not3^3 \\ \\ 3x = 3 . 2 \\ \\ 3x = 6 \\ \\ \\ \boxed{x = 2}$