Question

Como resolvo log 1/2 na base 2

Answer 1

log2(1/2) = log(1/2)/log(2) = 

(log(1) - log(2))/log(2) = 

-log(2)/log(2) = -1 

Answer 2

$\mathrm{\log_b{a}=x\ \to\ b^x=a\ \ \| \ \ \dfrac{1}{n}=n^{-1}}\\\\ \mathrm{\log_2{\dfrac{1}{2}}=x\ \to\ 2^x=\dfrac{1}{2}\ \to\ 2^x=2^{-1}\ \to\ x=-1}\\\\ \mathbf{\log_2{\dfrac{1}{2}}=-1}$