Question

como resolvo ? fazendo favor

Answer 1

Olá,

3)

$\sqrt{72}+ \sqrt{A}=11 \sqrt{2} \\ \sqrt{A}=11 \sqrt{2}-6 \sqrt{2}\\ \sqrt{A}=5\sqrt{2}\\ (\sqrt{A})^2=(5\sqrt{2})^2\\ A=25*2\\ \boxed{A=50}$

$\sqrt{126}+3 \sqrt{56}=B\\ 3\sqrt{14} +6 \sqrt{14}=B\\ \boxed{B=9 \sqrt{14}}$

4) 

$a= \sqrt{2} \\ b= \sqrt{3} \\ \sqrt{162}- \sqrt{588} + \sqrt{450} =(9 \sqrt{2}) - (14 \sqrt{3})+(15 \sqrt{2})=9a-14b+15a=\boxed{\ 24a-14b}$