Question

como resolvo estas esquaçoes de 2 grau
a)X²-4x-32=0
B)16X²+8x+1=0​

Answer 1

Resposta:

a )

${x}^{2} - 4x - 32 = 0 \\ \frac{4 + - \sqrt{ { - 4}^{2} - 4 \times 1 \times - 32} }{2} \\ \frac{ 4 + - \sqrt{16 + 128} }{2} \\ \frac{4 + - \sqrt{144} }{2} \\ \frac{4 + - 12}{2} \\ x1 = \frac{4 + 12}{2} = \frac{16}{2} = 8 \\ x2 = \frac{4 - 12}{2} = \frac{ - 8}{2} = - 4$

b)

${16x}^{2} + 8 + 1 = 0 \\ \frac{ - 8 + - \sqrt{ {8}^{2} - 4 \times 16 \times 1} }{32} \\ \frac{ - 8 + - \sqrt{64 - 64} }{32} \\ \frac{ - 8 + - 0}{32 } = \frac{ - 8}{32} = - \frac{ - 1}{4}$