Question

Como resolvo esses logaritmos?
a)   
Log
(3 * 5)
b)    Log (3* 6* 5*)

Answer 1

a) log (3 . 5) = log 3 + log 5 = 0,48 + 0,70 = 1,18

b) log (3 . 5 . 6) = log 3 + log 5 + log 6 = log 3 + log 5 + log (3 . 2) = log 3 + log 5 + log 3 + log 2 = 2 log 3 + log 5 + log 2 = 2 . 0,48 + 0,70 + 0,30 = o,96 + 0,70 + 0,30 = 1,96