Question

como resolvo esses logaritmos.?

Answer 1

$b)log _{625} \sqrt{5}=x \\ 625^x= \sqrt{5} \\ \not5^{4x}=\not5 ^{ \frac{1}{2} } \\ 4x= \frac{1}{2} \\ x= \frac{1}{2 } * \frac{1}{4} \\ \boxed{x= \frac{1}{8} } \\ \\ d)log _{49} \sqrt[3]{7} =x \\ 49^x= \sqrt[3]{7} \\ \not7 ^{2x} =\not7 ^{ \frac{1}{3} } \\ 2x= \frac{1}{3} \\ x= \frac{1}{3} * \frac{1}{2} \\ \boxed{x= \frac{1}{6} }$