Question

Como resolvo essa conta? Me ajudem por favor

Answer 1

$x^2-3=\frac{x-3}{6}$ =>
$6x^2-18=x-3$ =>
$6x^2-x-15=0$.


Bhaskara:

Δ$=b^2-4ac$ =>
Δ$=(-1)^2-4.6.(-15)$ =>
Δ$=1+360$ =>
Δ$=361$.

$x=-b\frac{+}{-}\sqrt{Δ}{2a}$ =>
$x=1\frac{+}{-}\sqrt{361}{2.6}$ =>

$x_{1}=\frac{1+19}{12}$ =>
$x_{1}=\frac{20}{12}$ =>
$x_{1}=\frac{5}{3}$.


$x_{2}=\frac{1-19}{12}$ =>
$x_{2}=\frac{-18}{12}$ =>
$x_{2}=-\frac{3}{2}$.

S = { $-\frac{3}{2},\frac{5}{3}$ }.