Question

como resolvo: 6(xao quadrado-1) -14=5x+x

Answer 1

6(x² - 1 ) - 14 = 5 x + x
6 x² - 6 - 14 = 5 x + x
6 x² - 20 = 6 x
6 x²- 6 x - 20 = 0
Δ = b² - 4.a.c
Δ = (-6)² - 4 .6 . -20
Δ = 36 +480
Δ = 516⇒√516 = √2².3.43 = 2 √129
x = - b + ou - 2√129 / 2.6
x´= -(-6) + 2√129/12
x´= 6 + 2 √129/12
x´= 3 + 1 .√129/6
x´´ = 6 - 2√129/12
x´´ = 3 - 1.√129/6
S = {3 + √129/6 ; 3 - √129/6 }