Question

como resolver: y= raiz (3x+1) -4

Answer 1

$y=( \sqrt{3x+1})-4$

$\sqrt{3x+1}-4=0$

$\sqrt{3x+1}=4-->( \sqrt{3x+1})^2=4^2$

$3x+1=16-->3x=15-->x=5$

$y=( \sqrt{3.5+1)}-4$

$y= (\sqrt{15+1})-4-->y= \sqrt{16}-4=4 - 4 = 0$