Question

Como resolver..
X(x+2)=3

Answer 1

x(x+2) = 3
x² +2.x - 3 = 0

Δ = b² - 4.a.c
Δ = (2)² - 4.1.(-3)
Δ = 16

$x' = \frac{-2+ \sqrt{16} }{2} ---\ \textgreater \ x = \frac{-2+4}{2} ---\ \textgreater \ x' = 1$$x'' = \frac{-2 - \sqrt{16} }{2} ---\ \textgreater \ x'' = \frac{-2-4}{2} ---\ \textgreater \ x'' = -3$

Answer 2

x(x + 2) = 3
x² + 2 x = 3
x² + 2 x - 3 = 0
Δ = b² - 4 .a.c
Δ = 2² - 4.1.-3
Δ = 4 + 12
Δ = 16 ⇒√16 = 4
x = - b + ou - 4/2.1
x´= -2 + 4/2 ⇒2/2 = 1
x´´ = -2 - 4/2 ⇒ - 6/2 = -3
S = {-3 ; 1 }