Question

como resolver x ao quadrado+8x+7=0​

Answer 1

Resposta:

Explicação passo-a-passo:

x²+8x+7=0

vamos utilizar baskara

a=1

b=8

c=7

b²-4.a.c

8²-4.1.7

64-28

36

raiz de √36 é 6

X=-b+-√36/2.a

X=-8+-6/2

X¹=-8+6/2 = -2/2= -1

X²=-8-6/2= -14/2= -7

S={-1,-7}

Answer 2

Vamos lá...

$x^2+8x+7=0\\\\Coeficientes:\;a=1,\;b=8\;e\;c=7\\\\\Delta=b^2-4ac\\\Delta=8^2-4\cdot1\cdot7\\\Delta=64-28\\\Delta=36\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-8\pm\sqrt{36}}{2\cdot1}\\\\x=\dfrac{-8\pm6}{2}\\\\x_8=\dfrac{-8+6}{2}=\dfrac{-2}{2}=-1\\\\x_8=\dfrac{-8-6}{2}=\dfrac{-14}{2}=-7$

Espero ter ajudado