Question

como resolver passo a passo
(x + 2) ^2 + (3x - 1)^2

Answer 1

$(x+2)^2+(3x-1)^2= \\ \\ =x^2+2.2x+2^2+9x^2-6x+1= \\ \\ =x^2+9x^2+4x-6x+4+1= \\ \\ =10x^2-2x+5$