como resolver o sistema linear utilizando escalonamento
3x-8y-9z=14
7x+3y+2z= -12
-8x-9y+6z=11
Soluções para a tarefa
Resposta:
3x-8y-9z=14
7x+3y+2z= -12
-8x-9y+6z=11
3 -8 -9 14
7 3 2 -12
-8 -9 6 11
L1=(1/3)*L1
L2=(1/7) * l2
L3=(1/8)* L3
1 -8/3 -3 14/3
1 3/7 2/7 -12/7
-1 -9/8 6/8 11/8
L2=L2-L1
L3=L3+L1
1 -8/3 -3 14/3
0 1 69/65 -134/65
0 -1 -54/91 145/91
L2=(21/65)*L2
L3=(24/91) * L3
1 -8/3 -3 14/3
0 1 69/65 -134/65
0 -1 -54/91 145/91
L3=L3+L2
1 -8/3 -3 14/3
0 1 69/65 -134/65
0 0 213/455 -213/455
L3=(455/213)*L3
1 -8/3 -3 14/3
0 1 69/65 -134/65
0 0 1 -1
L2=L2-(69/65)*L3
L1=L1+3L3 14/3 -3
1 -8/3 0 5/3
0 1 0 -1
0 0 1 -1
L1=L1+L2 * (8/3)
1 0 0 -1
0 1 0 -1
0 0 1 -1
Resposta ==> x=y=z=-1