Question

Como resolver o logaritmo de 125³ na base 1/5

Answer 1

$log_{ \frac{1}{5}}\ 125^3\\ \\=log_{ \frac{1}{5}}\ (5^3)^3\\ \\=log_{ \frac{1}{5}}\ 5^9\\ \\=log_{ \frac{1}{5}}\ ( \frac{1}{5} )^{-9}\\ \\=-9\cdot log_{ \frac{1}{5}}\ ( \frac{1}{5} )\\ \\=-9\cdot1\\ \\=-9$