Question

Como resolver,no conjunto ir,a equação? (2x+1)2=8+2 (2x+1)

Answer 1

$(2x+1)^2=8+2(2x+1) \\ \\ 4x^2+4x+1=8+4x+2 \\ \\ 4x^2+\not4x-\not4x=10-1 \\ \\ 4x^2=9 \\ \\ x^{2} = \frac{9}{4} \\ \\ x=\pm \sqrt{ \frac{9}{4} } \\ \\ x=\pm \frac{3}{2} \\ \\ S=\{- \frac{3}{2} ,+ \frac{3}{2} \}$

Answer 2

$(2x + 1)2 = 8 + 2(2x + 1) \\ 4x + 2 = 8 + 4x + 2 \\ 4x - 4x = 8 + 2 - 2 \\ 0x = 8$