Question

Como resolver log 2 de 0,25?

Answer 1

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}log_2\ 0,25=x\\\\2^x = 0,25\\\\2^x = \frac{1}{4}\\\\2^x = 4^{-1}\\\\2^x = 2^{-2}\\\\\boxed{x = -2}\\\\ \boxed{\boxed{S=\{-2\}}}} \end{array}\right$

Espero ter ajudado. :))