Question

como resolver log 144 sabendo q log2 = 0.301 log3 = 0.477 log7 = 0.845

Answer 1

Use a P2 e a P3,

$\log_b(a)^n=n\cdot \log_b(a)\\\\\log_a(bc)=\log_a(b)+\log_a(c)$

Aí decomponha 144 em fatores primos:

144|2
  72|2
  36|2
  18|2
    9|3
    3|3______
    1| $2^4\cdot3^2$


$\log144=\log[(2)^4\cdot(3)^2]\\ \log144=\log(2)^4+\log(3)^2\\ \log144=4\cdot\log(2)+2\cdot\log(3)\\ \log144=4\cdot0,301+2\cdot0,477\\\\ \huge\boxed{\log144=2,158}$

TENHA ÓTIMOS ESTUDOS ;D