Question

como resolver isso, nao estou conseguindo

Answer 1

8^(3x) = [ 2^(5x/3) ] / 2^(2x-2)
2^(3*3x )*  2^(2x-2) = 2^(5x/3)
2^(9x) * 2^(2x)*2^(-2) = 2^(5x/3)
2^(11x-2) = 2^(5x/3)
11x-2 = 5x/3 
(11x-2)*3 = 5x
33x - 6 = 5x 
28x = 6 
x = 6/28
x = 3/14