Question

como resolver isso???

Answer 1

Olá!

$4^2 \cdot \big[2^4 : (10-2+8) \big] + 2^0 \\ = 4^2 \cdot \big[ 2^4 : (16) \big] + 1 \\ = 4^2 \cdot \big( 2^4 : 2^4 \big) + 1 \\ = 4^2 ( 2^{4-4}) + 1 \\ = 4^2 ( 2^0) + 1 \\ = 4^2 (1)+ 1 \\ = 4^2 + 1 \\ = 16 + 1 \\ = 17$

Answer 2

4^2 * ( 2^4 / (10 - 2 + 8))  + 2^0

= 16 * (16/16) + 1

= 16*1 + 1 = 17