Question

como resolver esta questão ?

Answer 1

$\frac{6}{10x-4} = \frac{4}{8x-20} \\ \\ 6(8x-20) = 4(10x-4) \\ 48x - 120 = 40x - 16 \\ 48x - 40x = -16 + 120 \\ 8x = 104 \\ x = \frac{104}{8} \\ \\ x = 13$

Answer 2

fica assim:
$\frac{6}{10x-4} = \frac{4}{8x-20} =6(8x-20)=4(10x-4)$
$48x-120=40x-16=48x-40x=-16+120$
$8x=104=x=104/4$
$x=13$