Question

como resolver esta operação 27+{14+3×[100÷(18-4×2)+7]}÷13

Answer 1

$27+\{14+3\times[100\div(18-4\times2)+7]\}\div13= \\ \\ 27+\{14+3\times[100\div(18-8)+7]\}\div13= \\ \\ 27+\{14+3\times[100\div10+7]\}\div13= \\ \\ 27+\{14+3\times[10+7]\}\div13= \\ \\ 27+\{14+3\times17\}\div13= \\ \\ 27+\{14+51\}\div13= \\ \\ 27+65\div13= \\ \\ 27+5=\fbox{ 32 }$