Question

como resolver esta equaçao : x²-8x+7=0 ?

Answer 1

a=1    b= -8 c = 7

Δ = b² - 4ac

Δ= (-8) ² - 4 . 1 . 7

Δ = 64 -28

Δ = 63

x = -b + √Δ /2a

x = -(-8) + √36/2.1

x = 8 + 6 /2

x' = 8 + 6 /2

x' = 14/2

x'= 7

x" = 8 - 6/2

x" = 2/2

x" = 1