Question

como resolver essas geratrizes de dizimas perioticas:   a) o,4242... b) 0,7272...c) 0,612612.. d) 0,135135.. ??

Answer 1

 a) o,4242...  =  42/99

b) 0,7272...    = 72/99

c) 0,612612..      = 612/999

d) 0,135135..    =135/999

Answer 2

a-10x=0,72                                                                                                                                 x=0,7272                                                                                                                                  9x=0                                                                                                                                     x=0/9                            e resolve as outras do mesmo olhando apartir de que casa começa a dividir e colocando se for apartir de uma casa e 10x de duas 100x e assim por diante e depois subtrai e dividi pelo numero se for possivel