Question

como resolver essas equações? já fiz a letra c

Answer 1

$a) 125^x=25\\\\5^{3^{x}}=5^2\\\\5^{3x}=2\\\\3x=2\\\\x = 2/3$

$b) 5.2^{x-1}=80\\\\2^{x-1}=80/5\\\\2^{x-1}=16\\\\2^{x-1}=2^4\\\\x-1=4\\\\x = 5$

$d)0.75^{x+1}=\frac{3}{4} \\\\0.75^{x+1}=0.75^1\\\\x+1 = 1\\\\x = 0$

$e)(\frac{3}{5})^{5x}=( \frac{125}{27} )^2\\\\(\frac{3}{5})^{5x}=(\frac{5^3}{3^3})^2\\ \\(\frac{5}{3})^{-5x}=(\frac{5^3}{3^3})^2\\\\(\frac{5}{3})^{-5x}=(\frac{5}{3})^{3^2}\\\\(\frac{5}{3})^{-5x}=(\frac{5}{3})^{6}\\\\-5x = 6\\\\x = -6/5$