Question

Como resolver essa questão
$x + 1 = {x}^{2} - 1$

Answer 1

x+1= x²-1
2x²= -1-1
2x²= 2
x²= 1✓1

Answer 2

Olá, boa tarde!

$x+1=x^2-1 \\x^2-x-1-1=0\\x^2-x-2=0\\\\a=1,\;b=-1\;e\;c=-2\\\\\Delta=b^2-4ac\\\Delta=(-1)^2-4\cdot1\cdot(-2)\\\Delta=1+8\\\Delta=9\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-(-1)\pm\sqrt{9}}{2\cdot1}\\\\x=\dfrac{1\pm3}{2}\\\\x_1=\dfrac{1+3}{2}=\dfrac{4}{2}=2\\\\x_2=\dfrac{1-3}{2}=\dfrac{-2}{2}=-1$

Espero ter ajudado.

Bons estudos! :)