como resolver essa expresão
{4+2[25-1/4:(2/3-5/8)+2]-16}.1/4=
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{4+2[25-1/4:(2/3-5/8)+2]-16}.1/4=
![\{4+2[25-\frac{1}{4}:(\frac{2}{3}-\frac{5}{8})+2]-16\}:2=\\
\\
\{4+2[25-\frac{1}{4}:\frac{1}{24}+2]-16\}:2=\\
\\
\{4+2[25-8}+2]-16\}:2=\\
\\
\{4+2[19]-16\}:2=\\
\\
\{4+38-16\}:2=\\
\\
\{4+38-16\}:2=\\ \\ 26:2=13](https://tex.z-dn.net/?f=%5C%7B4%2B2%5B25-%5Cfrac%7B1%7D%7B4%7D%3A%28%5Cfrac%7B2%7D%7B3%7D-%5Cfrac%7B5%7D%7B8%7D%29%2B2%5D-16%5C%7D%3A2%3D%5C%5C%0A%5C%5C%0A%5C%7B4%2B2%5B25-%5Cfrac%7B1%7D%7B4%7D%3A%5Cfrac%7B1%7D%7B24%7D%2B2%5D-16%5C%7D%3A2%3D%5C%5C%0A%5C%5C%0A%5C%7B4%2B2%5B25-8%7D%2B2%5D-16%5C%7D%3A2%3D%5C%5C%0A%5C%5C%0A%5C%7B4%2B2%5B19%5D-16%5C%7D%3A2%3D%5C%5C%0A%5C%5C%0A%5C%7B4%2B38-16%5C%7D%3A2%3D%5C%5C%0A%5C%5C%0A%5C%7B4%2B38-16%5C%7D%3A2%3D%5C%5C+%5C%5C%C2%A026%3A2%3D13%0A "\{4+2[25-\frac{1}{4}:(\frac{2}{3}-\frac{5}{8})+2]-16\}:2=\\
\\
\{4+2[25-\frac{1}{4}:\frac{1}{24}+2]-16\}:2=\\
\\
\{4+2[25-8}+2]-16\}:2=\\
\\
\{4+2[19]-16\}:2=\\
\\
\{4+38-16\}:2=\\
\\
\{4+38-16\}:2=\\ \\ 26:2=13")
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