Question

Como resolver essa equação exponencial?

$2 . ( \frac{1}{4}) ^{2x-3} = 4$

Answer 1

$2\cdot\left(\dfrac{1}{4}\right)^{2x-3}=4$

$2\cdot\left(2^{-2})^{2x-3}=2^2$

$2\cdot2^{-4x+6}=2^2$

$2^{-4x+7}=2^2$

$-4x+7=2~~\Rightarrow~~4x=7-2~~\Rightarrow~~x=\dfrac{5}{4}$