Question

Como resolver essa Equaçao
(×-2)^2+4(×-1)(×+2)=16

Answer 1

(× -2)²            +4(×-1)(×+2) = 16
x² -2.x.2 + 2² +4x -4 +4x +8 = 16
x²   -4x   + 4  +4x -4 +4x +8 = 16
x² -4x +4x +4x +4 -4 +8 -16 = 0
x² +4x -12 = 0     >>>   eq. do 2. grau

Δ = b² - 4.a.c
Δ = 4² - 4.1.-12
Δ = 16 + 48
Δ = 64

x = -b +- √Δ / 2a
x = -4 +- 8 / 2

x' = -4 +8 / 2                           x'' = -4 -8 / 2
x' = 4/2                                   x'' = -12/2
x' = 2                                      x'' = -6