Question

como resolver essa derivada da funcao


f(x)=sen x
cos x

Answer 1

$f(x) = \frac{senx}{cosx}\\\\ f'(x) = \frac{sen'x*cosx-senx*cos'x}{(cosx)^2}\\\\\ f'(x)=\frac{cosx*cosx-(senx*-senx)}{cos^2x}\\\\ f'(x) = \frac{cos^2x+senx^2x}{cos^2x}\\\\ f'(x)=\frac{1}{cos^2x}\\\\ \large\boxed{f'(x)=sec^2x}}$