Question

Como Resolver Essa Conta

X2 - 8x + 12 = 0

Answer 1

$x^{2} -8x+12=0 \\ \Delta= (-8)^{2} -4*1*12=64-48=16 \\ \\ x = \frac{-(-8)\pm\sqrt{16}}{2} = \frac{8\pm4}{2} \\ \\ x_{1} = 6 \\ x_{2} =2$