Question

Como resolver em delta de 2° grau: x²+3=4x

Answer 1

x^2+3=4x
x^2-4x+3=0
delta=b^2-4ac
delta=(-4)^2-4.1.3
delta=16-12
delta=4
x=-b-/+ raiz de delta/2a
x=-(-4)-2/2.1
x=4-2/2
x=2/2
x=1
x=-(-4)+2/2.1
x=4+2/2
x=6/2
x=3

Answer 2

a=1 b=4 c=3
DELTA= 16-12
DELTA= 4

x= -4+ou-2/2

x1= -1
x2= -3