Question

como resolver com Bháskara?

$x^{2} - x - 2 =$

Answer 1

a= 1
b= -1
c= -2

∆=b²-4ac
∆=(-1)²-4×1×(-2)
∆=1+8
∆=9

x= -(-1)±√9/2×1
x=1±3/2
x¹= 1+3/2= 4/2= 2
x²= 1-3/2= 2/2 = 1