Question

Como resolver as equacoes
2(3x-1)+2 (3-x)=8
4 (x-2)+3 (2x-1)=6 (2x-3)
x-(x+1)=12-(3x-2)

Answer 1

a)
2(3x - 1) + 2(3 - x) = 8
6x - 2 + 6 - 2x = 8
6x - 2x - 2 + 6 =8
4x + 4 = 8
4x = 8 - 4
4x = 4
x = 4/4
x = 1

R.: x = 1
***************
_________________________________
b)
4(x - 2) + 3.(2x - 1) = 6.(2x - 3)
4x - 8 + 6x - 3 = 12x - 18
4x + 6x - 8 - 3 = 12x - 18
10x - 11 = 12x - 18
- 11 + 18 = 12x - 10x
18 - 11 = 2x
7 = 2x
2x = 7
x = 7/2

R.: x = 7
           2
*************
___________________________________
c)
x - (x + 1) = 12 - (3x - 2)
x - x - 1 = 12 - 3x + 2
0 - 1 = 14 - 3x
- 1 - 14 = - 3x
- 15 = - 3x  ( - 1)
15 = 3x
3x = 15
x = 15/3
x = 5

R.: x = 5 
*************

Answer 2

2(3x-1)+2(3-x)=8
6x-2+6-2x=8
6x-2x=8-6+2
4x=8-4
4x=4
x=4/4
x=1
4(x-2)+3(2x-1)=6(2x-3)
4x-8+6x-3=12x-18
4x+6x-12x=-18+3+8
4x-6x=-18+11
-2x=-7.(-1)
2x=7
x=7/2
x-(x+1)=12-(3x-2)
x-x-1=12-3x+2
x-x+3x=12+2+1
x+2x=15
3x=15
x=15/3
x=5