Question

como resolver a fórmula de Bhaskara x²-4x+4=0​

Answer 1

Boa Tarde !!!

$x^{2} - 4x + 4 = 0\\\\\Rightarrow Determinamos\ os\ coeficientes\\\\a = 1\\\\b = -4\\\\c = 4\\\\\Delta = b^2 - 4.a.c\\\\\Delta = (-4)^2-4.1.4\\\\\Delta = 16 - 16\\\\\Delta = 0\\\\x = \frac{-b\pm\sqrt{\Delta} }{2.a} \\\\x = \frac{4\pm0}{2} \\\\x' = \frac{4 + 0}{2}\\\\x' = 2\\\\x" = \frac{4-0}{2} \\\\x" = 2\\\\s = [2, 2]$

Espero ter ajudado :-)

Att: LDC

Answer 2

Resposta ↓

Conjunto solução ⇒ s = {2 ,2}

Explicação passo-a-passo:

x²-4x+4=0​

Coeficientes :

a = 1

b = - 4

c = 4

Δ = b² - 4.a.c

Δ = (-4)² - 4.1.4

Δ = 16 - 16

Δ = 0

$x = \cfrac{-b\pm\sqrt{\Delta} }{2.a} \\\\\\x = \cfrac{4\pm0}{2} \\\\\\x' = \cfrac{4 + 0 }{2} \\\\\\x' = \cfrac{4}{2} \\\\\\x' = 2\\\\\\x" = \cfrac{4}{2} \\\\\\x" = 2$