Question

COMO RESOLVER (5+7i)(3-2i) passo a passo

Answer 1

$Lembrando~que~~i=\sqrt{-1}~~~e,~consequentemente,~i^2=-1,~~temos:\\\\\\(5+7i).(3-2i)~=\\\\\\Aplicando~a~propriedade~distributiva~da~multiplicacao\\\\\\=~5~.~3~+~5~.~(-2i)~+~7i~.~3~+~7i~.~(-2i)~=\\\\\\=~15~-~10i~+~21i~-~14i^2~=\\\\\\=~15~+~11i~-14~.~(-1)~=\\\\\\=~15~+~11i~+~14~=\\\\\\=~\boxed{29+11i}$