Matemática, perguntado por henriquepyter, 1 ano atrás

como resolver 4t(2t - 5) = 3 - 4(2t +3)

Soluções para a tarefa

Respondido por Usuário anônimo
1
Boa tarde Henrique!

Solução!

4t(2t-5)=3-4(2t+3)\\\\\\
8t^{2}-20t=3-8t-12 \\\\\\
8t^{2}-20t+8t+12-3=0\\\\\
8t^{2}-12t+9=0

t= \dfrac{-(-12)\pm \sqrt{(-12)^{2}-4.8.9 } }{2.8} \\\\\\
t= \dfrac{12\pm \sqrt{144-288 } }{16} \\\\\\
t= \dfrac{12\pm \sqrt{-144 } }{16} \\\\\\
t= \dfrac{12\pm i\sqrt{144} }{16} \\\\\\
Raiz~~complexa\\\\\\\
t= \dfrac{12\pm 12i}{16} \\\\\\
t= 4(\dfrac{3\pm 3i}{4}) \\\\\\


t=3\pm 3i\\\\\
t_{1}=3+3i\\\\\\
 t_{2}=3-3i\\\\\\\\\\\\\\\\
\boxed{Resposta:S=\{3-3i,3+3i\}}

Boa tarde!
Bons estudos!



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