Question

como resolver 3x=√10-2x +7

Answer 1

3x = $\sqrt{10-2x}$ + 7
$(3x-7)^{2}$ = 10 - 2x
9 . $x^{2}$ - 42x + 49 = 10 -2x
9 . $x^{2}$ - 40x - 39 = 0
x = (40 + $\sqrt{1600 - 1404}$) ÷ 18
x = (40 + 14) ÷ 18 = 3
x = (40 - 14) ÷ 18 
x = 26 ÷ 18 = $\frac{13}{9}$