Question

como resolver 36 sobre √10-2?

Answer 1

$\frac{36}{\sqrt{10}-2}*\frac{\sqrt{10}+2}{\sqrt{10}+2}=\frac{36(\sqrt{10}+2)}{6}=6(\sqrt{10}+2)$

Answer 2

$\frac{36}{ \sqrt{10}-2 } . \frac{ (\sqrt{10}+2) }{ (\sqrt{10}+2 )} = \frac{36 \sqrt{10}+ 72}{10-4} = \frac{36 \sqrt{10}+ 72}{6} = 6 \sqrt{10} +12$