Question

como resolver 2/3 com expoente -3 no dois e expoente -4 no tres - 1/8

Answer 1

$\frac{ 2^{-3} }{ 3^{-4} } - \frac{1}{8}$


$\frac{ \frac{1}{2} ^{3} }{ \frac{1}{3} ^{4} } - \frac{1}{8}$


$\frac{ \frac{1}{8} }{ \frac{1}{81} } - \frac{1}{8}$


$\frac{1}{8} . \frac{81}{2} - \frac{1}{8}$


$\frac{81}{16} - \frac{1}{8}$


$\frac{81}{16} - \frac{2}{16} = \boxed{\boxed{\frac{79}{16} }}\ \ \ \ \ \ \ \ \ \ ok$