Question

como resolver 10+{(3^4-2^5)-7^2}​

Answer 1

Resposta:

$10+\left[\begin{array}{ccc}(3^{4}-2^{5})-7^{2} \end{array}\right]= \\ \\ 10+\left[\begin{array}{ccc}(27-32)+49 \end{array}\right]= \\ \\ 10+(-5)+49=\\ \\ 10-5+49=\\ \\ 54$

Answer 2

Explicação passo-a-passo:

10+[(3^4-2^5)-7^2]

10+[3^4-2^5)-7^2]

3^4

3×3×3×3

81

10+[(3^4-2^5)-7^2]

10+[(81-2^5)-7^2]

10+[(3^4-2^5)-7^2]

2^5

2×2×2×2×2

32

10+[3^4-2^5)-7^2]

10+[(81-32)-7^2]

10+[3^4-2^5)-7^2]

7^2

7×7

49

10+[(3^4-2^5)-7^2]

10+[(81-32)-49]

10+[49-49]

10+[0]

10+0

10

Resposta

10