Question

como resolver (1-i)^16

Answer 1

$(1-i)^{16} = ( (1-i)^{2} )^{8} = ( 1^{2} - 2.1.i + i^{2}) ^{8} = (1 - 2i -1)^{8} = (-2i)^{8} \\ = (-2)^{8} i^{8} =256 i^{0} =256.1=256$