Question

como resolve x + 2 sobre 6 + x + 1 sobre 4 = 6

Answer 1

x + 2 sobre 6 + x + 1 sobre 4 = 6

MMC:
6, 4|2
3, 2|2
3, 1|3
1, 1    

     2x2x3 = 12


$x+ \dfrac{2}{6} +x+ \dfrac{1}{4} =6\\\\\\ \dfrac{12x}{12}+ \dfrac{4}{12} + \dfrac{12x}{12}+ \dfrac{3}{12}= \dfrac{72}{12} \\\\\\\\ \dfrac{24x}{12} = \dfrac{72}{12} - \dfrac{7}{12}\\\\\\ \dfrac{24x}{12}= \dfrac{65}{12}\\\\\\ 24x= \dfrac{65}{12} \times 12\\\\24x= \dfrac{780}{12} \\\\24x=65\\\\x= \dfrac{65}{24}$



Forte abraço!

Answer 2

$x+ \frac{2}{6} +x+ \frac{1}{4} =6 \\ \\ (1+1)x+ \frac{1}{3} + \frac{1}{4} =6 \\ \\ mmc(3,4) =12 \\ \frac{2*12x+ 1*4 +1*3}{12} = \frac{6*12}{12} \\ \\ 24x+7=72 \\ 24x=65 \\ \\ x= \frac{65}{24}$