Question

como resolve essas questões de matrizes preciso urgente

Answer 1

Resposta:

Explicação passo-a-passo:

1)

a) Quadrada de ordem 3

b) 1, 6 e $\sqrt{5}$

c) 0, -3 e 6

d)  $\sqrt{5}$

e) 0

2) Seja a matriz A composta pelos seguintes elementos

a11 = 1 - 3.1 = 1 - 3 = -2

a12 = 1 + 2.2 = 1 + 4 = 5

a13 = 1 + 2.3 = 1 + 6 = 7

a21 = 2 + 2.1 = 2 + 2 = 4

a22 = 2 - 3.2 = 2 - 6 = -4

a23 = 2 + 2.3 = 2 + 6 = 8

a31 = 3 + 2.1 = 3 + 2 = 5

a32 = 3 + 2.2 = 3 + 4 = 7

a33 = 3 - 3.3 = 3 - 9 = -6

Assim, a matriz será

$A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\a_{31}&a_{32}&a_{33}\end{array}\right]=>A=\left[\begin{array}{ccc}-2&5&7}\\4&-4&8\\5&7&-6\end{array}\right]$

3)

a)

$A-B=\left[\begin{array}{cc}2&-3\\4&-1\\\end{array}\right]-\left[\begin{array}{cc}0&1\\2&3\\\end{array}\right]=>A-B=\left[\begin{array}{cc}2-0&-3-1\\4-2&-1-3\\\end{array}\right]=>A-B=\left[\begin{array}{cc}2&-4\\2&-4\\\end{array}\right]$

b)

$B^{t}=\left[\begin{array}{cc}0&2\\1&3\\\end{array}\right]$

Logo

$A+B^{t}=\left[\begin{array}{cc}2&-3\\4&-1\\\end{array}\right]+\left[\begin{array}{cc}0&2\\1&3\\\end{array}\right]=>A+B^{t}=\left[\begin{array}{cc}2+0&-3+2\\4+1&-1+3\\\end{array}\right]=>A+B^{t}=\left[\begin{array}{cc}2&-1\\5&2\\\end{array}\right]$