Question

Como resolve essas equações 

2x²+3x=0
-x² + 6x = 0
x²- 3600 =0
x²+27=0
4x²-49=0
x²-24=0

Answer 1

$a)2 x^{2} +3x=0$

$x(2x+3)=0$

$\boxed{\boxed{S=(0,-\frac{3}{2})}}$


$b)- x^{2} +6x=0$

$x(-x+6)=0$

$\boxed{\boxed{S=(0,6)}}}$


$c) x^{2} -360=0$

$x= \sqrt{3600}$

$\boxed{\boxed{S=(\pm60)}}}$


$d) x^{2} +27=0$

$x= \sqrt{-27}$

$\boxed{\boxed{S=(conjunto \left vazio)}}}$


$e)4 x^{2} -49=0$

$4 x^{2} =49$

$x^{2} = \frac{49}{4}$

$x= \sqrt{ \frac{49}{4} }$

$\boxed{\boxed{S=(\pm \frac{7}{2})}}}$


$f) x^{2} -24=0$

$x^{2} =24$

$x= \sqrt{24}$

$\boxed{\boxed{S=(\pm2 \sqrt[3]{3})}}$


Espero ter ajudado, bons estudos!