como resolve essa equação? -2x²+3x+5=0
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resolve por bhaskarq ou por som e produto
victorrafael145:
soma:-b/a e o prduto e c/a
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2x2-3x-5=0 Two solutions were found : x = -1 x = 5/2
Step by step solution :Step 1 :Simplify 2x2-3x - 5 Trying to factor by splitting the middle term 1.1 Factoring 2x2-3x-5
The first term is, 2x2 its coefficient is 2 .
The middle term is, -3x its coefficient is -3 .
The last term, "the constant", is -5
Step-1 : Multiply the coefficient of the first term by the constant 2 • -5 = -10
Step-2 : Find two factors of -10 whose sum equals the coefficient of the middle term, which is -3 .
-10 + 1 = -9 -5 + 2 = -3 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and 2
2x2 - 5x + 2x - 5
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x-5)
Add up the last 2 terms, pulling out common factors :
1 • (2x-5)
Step by step solution :Step 1 :Simplify 2x2-3x - 5 Trying to factor by splitting the middle term 1.1 Factoring 2x2-3x-5
The first term is, 2x2 its coefficient is 2 .
The middle term is, -3x its coefficient is -3 .
The last term, "the constant", is -5
Step-1 : Multiply the coefficient of the first term by the constant 2 • -5 = -10
Step-2 : Find two factors of -10 whose sum equals the coefficient of the middle term, which is -3 .
-10 + 1 = -9 -5 + 2 = -3 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and 2
2x2 - 5x + 2x - 5
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x-5)
Add up the last 2 terms, pulling out common factors :
1 • (2x-5)
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