como que calcula log de 125 na base 1/5??
Soluções para a tarefa
Respondido por
14
Boa tarde Daniel!
Solução!
![log_{ \frac{1}{5} }125\\\\\\
log_{ \frac{1}{5} }125=x\\\\\\
( \frac{1}{5})^{x}=125\\\\\\
(5^{-1})^{x}=5^{3}\\\\\\\
5^{-x}=5^{3}\\\\\\\
-x=3\\\\\\
\boxed{x=-3}](https://tex.z-dn.net/?f=log_%7B+%5Cfrac%7B1%7D%7B5%7D+%7D125%5C%5C%5C%5C%5C%5C%0Alog_%7B+%5Cfrac%7B1%7D%7B5%7D+%7D125%3Dx%5C%5C%5C%5C%5C%5C%0A%28+%5Cfrac%7B1%7D%7B5%7D%29%5E%7Bx%7D%3D125%5C%5C%5C%5C%5C%5C%0A%285%5E%7B-1%7D%29%5E%7Bx%7D%3D5%5E%7B3%7D%5C%5C%5C%5C%5C%5C%5C%0A5%5E%7B-x%7D%3D5%5E%7B3%7D%5C%5C%5C%5C%5C%5C%5C%0A-x%3D3%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7Bx%3D-3%7D%0A%0A+++++ "log_{ \frac{1}{5} }125\\\\\\
log_{ \frac{1}{5} }125=x\\\\\\
( \frac{1}{5})^{x}=125\\\\\\
(5^{-1})^{x}=5^{3}\\\\\\\
5^{-x}=5^{3}\\\\\\\
-x=3\\\\\\
\boxed{x=-3}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
danielck:
obrigado, ajudou muito
Dê nada!
Respondido por
1
Vejamos:
log(1/5)^125 = x
log5^-x = 5³
logo, x = -3
log(1/5)^125 = x
log5^-x = 5³
logo, x = -3
já haviam me respondido mas obrigado do mesmo jeito
Perguntas interessantes